VB.NET: Upload A File For Future Use Using UploadFile()

Instructions

Create a new Console Application project and add a web reference.

Copy the entire code below, delete anything written in your application and paste the code there.
Replace the values of the Const lines with your details:
- Replace MyUsername and MyPassword with your PostalMethods user details.
- Replace MyFileName with the name you would like to give the file. This name is used for future references to this file. Format: <file name>.<file extension>.
- Replace MyPathToFile with a full path to your file.
Start your application. If the response is -3000, you will see the status report. If the response is any other number, check the Web Service Status Codes section.

Imports System.IO
 
Module module1
    Sub Main()
        Const MyUsername As String = "MyUsername"
        Const MyPassword As String = "MyPassword"
        Const MyFileName As String = "PurchaseInvoice.mht"
        Const MyPathToFile As String = "C:\PurchaseInvoice.mht"
        ' You may download this file from http://www.postalmethods.com/files/templates/PurchaseInvoice.mht
 
 
        ' Set account permissions for this file: 
        Const MyPermissions As com.postalmethods.api.Permissions = com.postalmethods.api.Permissions.Account
        ' Set Overwrite mode:
        Const FileUploadOverwrite As Boolean = False
 
        Dim objPM As New com.postalmethods.api.PostalWS()
        Dim lngResult As Long
 
        ' Read file to upload and convert to binary. In this case, the file is C:\PurchaseInvoice.mht
        ' You may download this file from http://www.postalmethods.com/files/templates/PurchaseInvoice.mht
        Dim MyFile As Byte() = IO.File.ReadAllBytes(MyPathToFile)
 
 
        ' Invoke the UploadFile method
        lngResult = objPM.UploadFile( _
                                MyUsername, _
                                MyPassword, _
                                MyFileName, _
                                MyFile, _
                                MyPermissions, _
                                FileUploadOverwrite)
 
        ' 
        ' Check response status
        '
        If lngResult = -3000 Then
            '
            ' If the result code = -3000, the file was uploaded successfully and it is ready for use.
            '
            Console.WriteLine("File uploaded successfully!")
        Else
            '
            ' A negative value means an error occurred.
            ' See the PostalMethods Status Codes: http://www.postalmethods.com/statuscodes#webservice.
            '
            Console.WriteLine("An error occurred:" & lngResult)
        End If
 
        ' In debug mode, the following lines prevent your console application from closing automatically upon termination
        Console.WriteLine("Hit ENTER to terminate application")
        Console.ReadLine()
 
    End Sub
 
End Module

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VB.NET: Upload A File For Future Use Using UploadFile()

Instructions